Calculus
posted by Liz .
Find an equation of the line that is tangent to the graph of f and parallel to the given line.
Funtion:
f(x)=1/sqrt(x1)
Line:
x+2y+7=0

f'=1/2 * (x1)^1.5
that is the slope then tangent to the line.
y=x/23.5
so slope is 1/2
f'=1/2 * (x1)^3/2=1/2
solving, x=2
then
y=1/sqrt(x1)=1 so the point of tangency is 2,1
y=mx+b
2=1/2 (1)+b
b=2.5
y=x/2+2.5
check all this.