ALGEBRA
posted by Urgen please help .
Solve the equation. (Enter solutions from smallest to largest. If there is no solution, enter NONE in the answer boxes.)
4x2 = 19x + 5
x =
x =

4x^2 = 19x + 5.
4x^2  19x  5 = 0
Factor using AC method or Quad. Formula:
AC = 4 * (5) = 20 = 1*(20)
4x^2 + (x20x)  5 = 0
Arrange the tems to form 2 factorable binomials:
(4x^2+x) + (20x5) = 0
x(4x+1)  5(4x+1)
(4x+1)(x5) = 0
4x+1 = 0
4x = 1
X = 1/4.
x5 = 0
X =5.
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