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Consider a die with 8 sides, marked one, two, three, and so on. assuming equally likely outcome, find the probability that the sum of two dice is the given number. If p(10)=

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    There are 64 possible dice throw outcomes.
    The throws with sum 10 are:

    (2,8) (3,7) (4,6) (5,5) (6,4) (7,3) (8,2)

    Therefore P(10) is 7 out of 64 (7/64)

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