Mathematics
posted by INDIANA .
(in this question they did not give me any diagrams)
use pie 22/7
(a) a piece of wire is bent to form a square of area 121cm squared
Calculate the length of each side of the square.
Calculate the perimeter of the square.
(b) the same piece of wire was bent to form a circle.
Calculate the radius of the circle.
Calculate the area of the circle.
PLEASE EXPLAIN HOW YOU GOT EACH ANSWER THANK YOU.

first, it's "pi" not "pie"
121 = 11^2, so the wire is bent into an 11×11 square. 4 sides of 11cm = 44cm perimeter.
for a circle, the circumference is 2πr, and the area is πr^2. We have 122cm of wire, so c = 121. r = 121/2π = 19.26cm
the area of the circle is πr^2 = π(c/2π)^2 = c^2/4π = 121^2/4π = 1165cm^2 
How did you get 122cm of wire??

Come on, Indiana!
Could you not see that Steve made a simple typing error??
He did use the correct number of 121 in the very next line, so clearly no harm was done.
Both his answers are correct. 
A piece of wire is bent to form a square of area 121cm.
Calculate:
a)the length of each side of the square
b)the perimeter of the square
The piece of wire is now bent to form a circle using π=3.14
Calculate:
a)The radius of the circle 
area of the square = 121cm²
s² = 121
s = square root of 121
s = 11 cm
the length of each side of the square is 11cm.
perimeter of the square = 4s
= 4*11
= 44 cm
length of the wire = c of circle
121 cm = 2πr
121 cm = 2*22/7* r
r = 121 by 2 * 22/7
r = 19.26 cm
therefore,
area of the circle = πr²
= 22/7 * 19.26 * 19.26
= 1165 cm²
thank you!!