maths
posted by jennie cribzon .
divide 8 into two partssuch that the sum of their squares is 34

let x = first number
let 8x = second number
then we set up the equation. It says that the sum of their squares must be 34. thus,
x^2 + (8x)^2 = 34
then we solve for x:
x^2 + 64  16x + x^2 = 34
2x^2  16x + 64 = 34
2x^2  16x + 30 = 0
x^2  8x + 15 = 0
since it's factorable, we can just factor this, and not use the quadratic formula:
(x3)(x5) = 0
x = 3 (first number)
8x = 5 (second number)
if you get the x = 5, you will obtain same set of answers since 85 = 3.
hope this helps~ :)
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