Physics
posted by Don .
An electric drill operates at a potential difference of 120V and draws a current of 1.5 Amps. If it takes 50 seconds to drill a hole in a piece of steel,calculate the amount of electrical energy used by the drill in that time.

And the phase angle (power factor) is what?
I assume your teacher wants you to ignore that power drills are not inductive.
With that imagination,
power= energy/time
energy= power*time= VI*time=120*1.5*50 joules 
Hi bob, could you explain how you came to that calculation, please.
As in where did the 1.5 come from, and the 50 joules(it was 50 seconds) I'm lost, could you help?
Thanks 
energyinJoules=powerinwatts*timeinSeconds
= Voltageinvolts*CurrentinAmps*timeinSeconds 
Ahhh so its 120*7.5*50seconds
7.5 being the amps that the drill draws and 50 being the time and 120 being the voltage.
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