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A 6 mC charge experiences a force of 6 N directed north. What is the electric field (magnitude and direction) at the location of the charge?

Would the direction still be north? And the magnitude 1000?

  • Phys. -

    E = F/q = 6/6•10^-3 =100 V/m.

    The direction still be north.
    magnitude of the electric field is
    E = k •q /r²,
    therefore, E ~ 1/r²

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