posted by Cherie

When two die are tossed,throwing a sum of 7 is three times more likely than throwing a sum of 11.if the probability of throwing a sum of 11 is 1:18,what is the probability of throwing a sum of 7?

  1. Reiny

    why not just find the prob of getting a sum of 7 ?

    there are 6 ways to get a 7 (list them if you have to)

    prob of getting a sum of 7 = 6/36 = 1/6

    btw. prob of 11 :
    2 ways, either 5,6 or 6,5
    prob of 11 = 2/36 = 1/18 , as they stated
    and (3)(1/18) = 1/6
    (they just made the question complicated on purpose)

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