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Find the volume of the solid obtained by rotating the region bounded by the given curves about the x-axis?
y=x^2
x=y^2

about the axis x=–2

here's what i did and it was incorrect
V = 2pi [x+2][x^1/2 - x^2]dx from 0 to 1
V = 2 pi [2x^5/3 / 5 + 4x^3/2 / 3 - x^4/4 - 2x^3 / 3]
V = 49/60 :[

  • Math -

    i got it!!! i didn't multiply the answer by 2 pi -_- sorry!

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