posted by .

1. x^2 + y^2 = 20

2. y=x^2-2x+1

How would I go about solving these?

  • math -

    !. from the 2nd : y = 6-x
    sub into the 1st:
    x^2 + (6-x)^2 = 20
    x^2 + 36 - 12x + x^2 - 20 = 0
    2x^2 - 12x + 16 = 0
    x^2 - 6x + 8 = 0
    (x-4)(x-2) = 0
    x = 4 or x = 2

    2. from the 2nd: y = x+3
    sub into the 2nd
    proceed as above....
    let me know what you got

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math

    Hello! I need assistance in solving for a side for a right triangle in trigonometry. Can anyone give me the easiest way/formula how to go about solving it?
  2. Math

    If I traveled 3 miles in a day, how many hours did I travel?
  3. Math

    I need help on two problems. How would you go about solving: 1. 3(a-5) + 19= -2 2. -9 - 3(2q-1)= -18
  4. Algebra

    Explain the difference between solving a linear equation graphically and solving a system of equations graphically. How would I go about doing this?
  5. MATH

    Solving by graphing DQ 1 Solving by substitution Solving by elimination Which method do you think would be best to solve this system?
  6. math puzzle

    how would you go about solving this ive tryed everything. 2*2+7*3+4*3+3+4+3*2=?
  7. Calculus

    I am having trouble solving this problem: "Find where the tangent line is horizontal for r=1+cos(theta)" I would really appreciate the feedback, I'd like to know how to go about solving problems like these. Thank you!
  8. Math

    Can someone please explain to me exactly what type of math this is (e.g. radicals, linear equations) and how I would go about solving this?
  9. math

    How would I go about solving this problem?
  10. Math

    How would I go about solving y - 6 is greater than or equal to = 12?

More Similar Questions