posted by Jessica .
A rock is thrown horizontally off of a cliff. It starts with a velocity of 4.2 m/s and the cliff is 68.2 m high.
How far out from the bottom of the cliff does the rock fall?
time to fall from height of clift:
68.2=1/2 g t^2
t= sqrt (68.2/4.9)=3.7 sec
distance horizontal= time*initial velocity