the concentration of HCl, a strong acid is 0.500 M. if 20.0 ml HCl is needed to titrate 40.0 ml of NaOH, what is the concentration of NaOH
Help me please. I'm confused by this
Use this equation
M1V1=M2V2
To find the concentration of NaOH, we can use the following equation:
M1V1 = M2V2
Where:
M1 = concentration of HCl
V1 = volume of HCl used for titration
M2 = concentration of NaOH
V2 = volume of NaOH used for titration
In this case, we are given:
M1 = 0.500 M (concentration of HCl)
V1 = 20.0 mL (volume of HCl used for titration)
V2 = 40.0 mL (volume of NaOH used for titration)
Let's substitute the given values into the equation and solve for M2:
0.500 M * 20.0 mL = M2 * 40.0 mL
Now, let's solve for M2:
M2 = (0.500 M * 20.0 mL) / 40.0 mL
M2 = 0.25 M
Therefore, the concentration of NaOH is 0.25 M.