Pre-Calc Help!!!!!!!!

posted by .

1+sin2x/sin2x=1+1/2(secx)(cscx)

  • Pre-Calc Help!!!!!!!! -

    1 + sin2x = 1 + 2sinx cosx
    divide by 2sinx cosx to get

    1/(2sinx cosx) + 1
    = 1/2 cscx secx + 1

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. pre-cal

    find all solutions in interval [0,2pi] tan²x = -3/2 secx This question may look tricky, but its actually quite simple. First: rearrange the pythagorean identity tan²x+1=sin²x so that it reads tan²x=sin²x-1 Then replace the tan²x …
  2. pre-calc

    is x=15 degrees a solution of radical 3/3 cos2x+sin2x=0
  3. trigonometry

    if sin2x=3sin2y, prove that: 2tan(x-y)=tan(x+y) ( here, in sin2x, 2x is an angle., like there's a formula:sin2x=2sinxcosx and sin2y=2sinycosy; ....)
  4. Pre-Calculus

    Find a numerical value of one trigonometric function of x if tanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1 d)sinx=1/2
  5. Calc

    First make an appropriate substitution and then use integration by parts to evaluate the indefinite integrals: ∫ sinx cos³x e^(1-sin²x) dx I was going to substitute u= 1 - sin²x, but then i got du = ½ sinxcosx - ½ xdx, so …
  6. calculus

    d/dx(e^sinx2x)= a)-cos2xe^sinx2x b)cosxe^sin2x c)2e^sin2x d)2cos2xe^sin2x e)-2cos2xe^sin2x
  7. pre-calc

    tanx= -12/5 x in Q 2. find sin2x= cos2x= tan2x=
  8. Pre-Calc/Math

    Prove Identity: (1-cos2x/ tan x) = sin2x
  9. Pre Calculus

    (secx)/(tanx)+(cscx)/(cotx)=secx+cscx Please help me verify this trigonometric identity.
  10. Math please help quick

    Which of the following are identities? Check all that apply. (Points : 2) sin2x = 1 - cos2x sin2x - cos2x = 1 tan2x = 1 + sec2x cot2x = csc2x - 1 Question 4. 4. Which of the following equations are identities?

More Similar Questions