Math
posted by Mason .
Perform the indicated operations and simplify
i^37
sqr12 x sqr15

Math 
Reiny
for i^37
look at this pattern
i
i^2 = 1
i^3 = i^2(i) = i
i^4= i^2 i^2= (1)(1) = +1
i^5 = i
etc
if the exponent is a multiple of 4, the result is +1
so i^37 = (i^36)(i) = i
(√12) (√15)
= (√4√3 i)(√15 i)
= 2√45 i^2
= 6√3
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