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Math

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Perform the indicated operations and simplify

i^37


sqr-12 x sqr-15

  • Math -

    for i^37
    look at this pattern
    i
    i^2 = -1
    i^3 = i^2(i) = -i
    i^4= i^2 i^2= (-1)(-1) = +1
    i^5 = i
    etc
    if the exponent is a multiple of 4, the result is +1
    so i^37 = (i^36)(i) = i


    (√-12) (√-15)
    = (√4√3 i)(√15 i)
    = 2√45 i^2
    = -6√3

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