Post a New Question

TRIG

posted by .

Factor
4cos^2x+4cosx-1=0

  • TRIG -

    what is (2cosx+1-sqrt2)(2cos+1+sqrt2)

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Calculus

    f(x)=4sinx/1+cosx find f'(x) this is what i got and i dunno what i did to get it wrong (4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62
  2. calculus please help me

    Let f(x)=9sinx/2sinx+4cosx. Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where m= 9and b= ______.?
  3. More trig

    Use the Quadratic Formula to solve the equation in the interval [0,2pi). Then use a graphing utility to approximate the angle x. (1) 5/(tanx+secx) (2) 4cos^2x-4cosx-1=0 Thank you.
  4. pre-cal

    What are the steps for solving this? Directions Use the quadratic formula to solve the equation in the interval [0,2PI). Then use a graphing utility to approximate the angle x. 4cos^2x-4cosx-1=0 thanks.
  5. trig

    Factor each expression: cos^2x- 2cosx+1 4cos^2x-1
  6. math

    find all solutions of the equation 4cos^2x-4cosx+1=0
  7. trig

    express in terms of ¦Ð, the interval for which 4cosx ¡Ý 2
  8. Trig

    Factor 4cos^2x+4cosx-1=0
  9. trig

    Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the max displacement occurs when t=0. answers: y=4sin pi t, y=4cos pi t, y=4cos t, y=4sin2 pi t
  10. Math - trig

    Determine the general solution of 8 cos^2x - 4cosx - 1 =0 (8cos^2x - 4cosx)/8 =1/8 cos^2x - 4cosx=1/8 cos^2x/cosx =1+4cosx/cosx cosx = 5 x = cos^-1(5) x = error

More Similar Questions

Post a New Question