# TRIG

posted by .

Factor
4cos^2x+4cosx-1=0

• TRIG -

what is (2cosx+1-sqrt2)(2cos+1+sqrt2)

## Similar Questions

1. ### Calculus

f(x)=4sinx/1+cosx find f'(x) this is what i got and i dunno what i did to get it wrong (4cos(x)+ 4cosx^2-4sin(x)^2)/cosx62

Let f(x)=9sinx/2sinx+4cosx. Then 'f(x)= ((2sinx+4cosx)(9cosx)-(9sinx)(2cosx-4sinx))/(2sinx+4cosx)^2. The equation of the tangent line to y=f(x) at a=2 can be written in the form y=mx+b where m= 9and b= ______.?
3. ### More trig

Use the Quadratic Formula to solve the equation in the interval [0,2pi). Then use a graphing utility to approximate the angle x. (1) 5/(tanx+secx) (2) 4cos^2x-4cosx-1=0 Thank you.
4. ### pre-cal

What are the steps for solving this? Directions Use the quadratic formula to solve the equation in the interval [0,2PI). Then use a graphing utility to approximate the angle x. 4cos^2x-4cosx-1=0 thanks.
5. ### trig

Factor each expression: cos^2x- 2cosx+1 4cos^2x-1
6. ### math

find all solutions of the equation 4cos^2x-4cosx+1=0
7. ### trig

express in terms of ¦Ð, the interval for which 4cosx ¡Ý 2
8. ### Trig

Factor 4cos^2x+4cosx-1=0
9. ### trig

Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the max displacement occurs when t=0. answers: y=4sin pi t, y=4cos pi t, y=4cos t, y=4sin2 pi t
10. ### Math - trig

Determine the general solution of 8 cos^2x - 4cosx - 1 =0 (8cos^2x - 4cosx)/8 =1/8 cos^2x - 4cosx=1/8 cos^2x/cosx =1+4cosx/cosx cosx = 5 x = cos^-1(5) x = error

More Similar Questions

Post a New Question