posted by Neptoh
A bubble located 0.200m beneath the surface of a glass of beer rises to the top.the air pressure at the top of the glass is 1.01(10^5)pa.assume that the density of beer is the same as that of fresh water at 4 degrees celcius.if the temperature and number of moles of CO2 remain constant as the bubble rises,calculate the ratio of its volume at the top to that at the bottom
you have a pressure difference of 20cm of beer.
P1=P2+ beer heightpressure
solve for V2/V1