math
posted by jim .
A circular pool has a diameter of 3m and is filled to a depth of 70 cm. Mr Thorpe climbs into the pool and submerges for ten seconds while his son measures the new depth at 72 cm. Calculate Mr Thorpe’s volume

According to Archimedes, Mr. Thorpe displaced his own volume.
old volume of pool = π(1.5)^2 (.70) = 1.575π m^3
volume after he stepped in = π(1.5)^2 (.72) = 1.62π m^3
difference
= Mr. Thorpes' volume
= .045P m^3 or 45000π cm^3
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