maths
posted by mumba .
the equation of the circle is x^2+y^2+2x8y1=0.
Find the coordinates of the point where the circle crosses the xaxis

y will equal 0 where the circle crosses the x axis.
x^2 +2x 1 = 0
x = (1/2)[2 +/sqrt8]
= 1 +/sqrt2
= 2.414 and 0.414