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the equation of the circle is x^2+y^2+2x-8y-1=0.
Find the coordinates of the point where the circle crosses the x-axis

  • maths -

    y will equal 0 where the circle crosses the x axis.

    x^2 +2x -1 = 0

    x = (1/2)[-2 +/-sqrt8]
    = -1 +/-sqrt2
    = -2.414 and 0.414

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