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A 55.0 kg circus performer oscillates up and down at the end of a long elastic rope at a rate of once every 7.20 s. The elastic rope obeys Hooke's Law. By how much is the rope extended beyond its unloaded length when the performer hangs at rest?

  • physics -

    The period of oscillations is
    T = 2•π•sqr(m/k)
    k= 4• π^2•m/T^2 =41.84 N/m

    Hook’s law: F = - kx, F=-mg
    mg = kx,
    x=mg/k=55•9.8/41.84 =12.88 m

  • physics -

    Thank you , Elena.

  • physics -

    Thank you!

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