physics
posted by Katie .
A 55.0 kg circus performer oscillates up and down at the end of a long elastic rope at a rate of once every 7.20 s. The elastic rope obeys Hooke's Law. By how much is the rope extended beyond its unloaded length when the performer hangs at rest?

physics 
Elena
The period of oscillations is
T = 2•π•sqr(m/k)
k= 4• π^2•m/T^2 =41.84 N/m
Hook’s law: F =  kx, F=mg
mg = kx,
x=mg/k=55•9.8/41.84 =12.88 m 
physics 
bobpursley
Thank you , Elena.

physics 
Katie
Thank you!
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