Math
posted by Anonymous .
Find the maximum value of f(x)=5x^(2/3)x^(5/3) on [1,4].
thank you!

f' = 10/3 x^(1/3)  5/3 x^(2/3)
= 5/3 x^(1/3) * (2x)
so, a max/min occurs in this interval only at x=2.
f(1) = 4
f(2) = 4.7
f(4) = 2.5
so I'd say it's a max
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