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Given the equation of an ellipse as
5x^2+3y^2-15=0
find the centre and foci

  • maths -

    change it to the standard form of an ellipse.

    5x^2 + 3y^2 = 15
    divide each term by 15

    x^2 /3 + y^2 /5 = 1

    centre is (0,0)
    a = √3 , b=√5
    c^2 + √3^2 = √5^2
    c^2 + 3 = 5
    c^2 = 2
    c = ± √2

    foci : (0,√2) and (0,-√2) , (on the y-axis)

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