# math

posted by .

A town has a population of 32,000 in the year 2002; 35,200 in the year 2003; 38,720 in the year 2004; and 42,592 in the year 2005. If this pattern continues, what will the population be in the year 2016?

• math -

Consider the increase per year:
2002-2003: 3200 factor of 1.100
2003-2004: 3520 factor of 1.100
2004-2005: 3872 factor of 1.100

This is obviously a geometric series. The population increases 10% per year, like compound interest. After 14 years (if the trend continues) , the population is
(1.1)^14*32000 = 121,520

## Similar Questions

1. ### College Algebra

The following graph shows Bobâ€™s salary from the year 2002 to the year 2005. He was hired in the year 2002; therefore t = 0 represents the year 2002. These are the points on the graph! O year = \$41000 1 year = \$43000 2 year = \$46000 …
2. ### Algebra 115

I have been trying this on my own and just want to know if this is right are not 2. Suppose that the linear equation y = 0.3x + 0.9 represents an estimate of the average cost of gas for year x starting in 2002. The year 2002 would …
3. ### algebra 1 sequences

Year 2003 2004 2005 2006 Populatation 22.12 22.49 22.86 23.41 A. divide the population for each year by the population in the preceeding year. Round to the two decimal places and show the Texas population increase that is approximately …
4. ### Algebra sequences

Year 2003 2004 2005 2006 Populatation 22.12 22.49 22.86 23.41 A. divide the population for each year by the population in the preceeding year. Round to the two decimal places and show the Texas population increase that is approximately …
5. ### Goodwill Valuation 2 - Accountancy

In case of Admission: Given a balance sheet as at 31 Dec 2007. The new partner was admitted on 1 Jan 2007. Goodwill was agreed at 2 years purchase and was to be valued in accordance to the weighted average gross profit method for the …
6. ### Math 208

Question number 5 is talking about a public four-year college. So we know this: 2000-\$3,500 2001-\$3,700 2002- ?
7. ### Calculus

The population in certain country is growing at the rate of 7 % a year . If the population in the year 1995 was 190 million, (a)determine an exponential expression representing the population as a function of the year. (b) What will …
8. ### Algebra

On Jan 1, 2010, Chessville has a population of 50,000 people. Chessville then enters a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville …
9. ### Algebra

On Jan 1, 2010, Chessville has a population of 50,000 people. Chessville then enters a period of population growth. Its population increases 7% each year. On the same day, Checkersville has a population of 70,000 people. Checkersville …
10. ### Algebra II

1. Which represents the type of sequence: 33, 31, 28, 24, 19,... option a. option b. option c. option d. 2. A town has a population of 32,000 in the year 2002; 38,400 in the year 2003; 46,080 in the year 2004; and 55,296 in the year …

More Similar Questions