Calculus ap

posted by lily

Use implicit differentiation to find the slope of the tangent line to the curve XY^3 + XY = 5 at the point (3,2) .

  1. bobpursley

    3Y^2 x dy+ Y^3 dx+ x dy+ y dx=0

    dy(3xy^2+x)=-dx(y+y^3)

    dy/dx= slope= -(y^3+y)/(3xy^2+x)

    put in the x,y and solve.

    check my work, I did it in a hurry.

  2. LILY

    i got the answer right thanks

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