What are the accepted values for the number of moles of NaCl that are produced from HCl and the following various amounts of grams of NaHCO3;
0.25 grams
0.5 grams
1 gram
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All of these are done alike. I'll do the first one.
HCl + NaHCO3 ==> H2O + NaCl + CO2
mols NaHCO3 = grams/molar mass = 0.25/84 = 0.00298.
mols NaCl = mols NaHCO3 (from the 1:1 ratio in the balanced equation.)
Therefore mols NaCl from 0.25 mols NaHCO3 = 0.0030 mols to two significant figures.
To find the number of moles of NaCl produced from HCl and different amounts of NaHCO3, we need to use the balanced chemical equation for the reaction between HCl and NaHCO3. The balanced equation is as follows:
2 HCl + NaHCO3 -> CO2 + H2O + NaCl
From the balanced equation, we can see that 2 moles of HCl react with 1 mole of NaHCO3 to produce 1 mole of NaCl.
Now, let's calculate the number of moles of NaCl produced for each given amount of NaHCO3:
For 0.25 grams of NaHCO3:
To determine the number of moles, we need to use the molar mass of NaHCO3, which is 84 grams/mol.
Number of moles of NaHCO3 = mass of NaHCO3 / molar mass of NaHCO3
Number of moles of NaHCO3 = 0.25 grams / 84 grams/mol
Number of moles of NaHCO3 = 0.00298 mol
Since the stoichiometric ratio between NaHCO3 and NaCl is 1:1, the number of moles of NaCl produced will also be 0.00298 moles.
For 0.5 grams of NaHCO3:
Number of moles of NaHCO3 = 0.5 grams / 84 grams/mol
Number of moles of NaHCO3 = 0.00595 mol
Again, the number of moles of NaCl produced will be 0.00595 moles.
For 1 gram of NaHCO3:
Number of moles of NaHCO3 = 1 gram / 84 grams/mol
Number of moles of NaHCO3 = 0.0119 mol
The number of moles of NaCl produced will be 0.0119 moles.
Therefore, the accepted values for the number of moles of NaCl that are produced from HCl and the given amounts of grams of NaHCO3 are:
- For 0.25 grams of NaHCO3, the number of moles of NaCl is 0.00298 moles.
- For 0.5 grams of NaHCO3, the number of moles of NaCl is 0.00595 moles.
- For 1 gram of NaHCO3, the number of moles of NaCl is 0.0119 moles.