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western

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9.11 g of CuBr2 contains how many bromide (Br-) ions?

  • western -

    Cu --> 63.5 g/mol
    Br --> 80 g/mol
    63.5 + 160 = 223.5 g/mol
    so
    # of moles = 9.11/223.5 * 6*10^23
    = .245 * 10^23 molecules
    twice that many Br- ions so
    .49 * 10^23 or 4.9*10^22 ions

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