The magnetic force on a straight wire .69 m long is 1.5 x 10^-3 N. The current in the wire is 16.9 A. What is the magnitude of the magnetic field that is perpendicular to the wire?
F = B I L
Solve for B, in units of Tesla
B = F/(L*I) = 1.5*10^-3/(0.69*16.9)
= ___ T
here
To determine the magnitude of the magnetic field, we can use the formula for the magnetic force on a straight wire:
F = BIL
Where:
F is the magnetic force
B is the magnetic field
I is the current
L is the length of the wire
Rearranging the formula, we can solve for the magnetic field:
B = F / (IL)
Given:
F = 1.5 x 10^-3 N
I = 16.9 A
L = 0.69 m
Substituting the given values into the formula:
B = (1.5 x 10^-3 N) / (16.9 A × 0.69 m)
Now, we can calculate the value of B:
B = 1.5 x 10^-3 N / (11.661 A·m)
Calculating this expression gives us:
B ≈ 1.286 x 10^-4 T
Therefore, the magnitude of the magnetic field perpendicular to the wire is approximately 1.286 x 10^-4 Tesla.