How many 4 digit combinations can you get using numbers 0-9..?
If zero is allowed to be a leading digit, then
10*10*10*10 if numbers can be repeated.
Yeah, I figured it's 10,000..but I'm trying to see if there are all 10,000 combinations online somewhere. I doubt it though.
you can write them down in a few hours.
start with
0000
0001
0002, and so on. Have fun.
I tried, It just confused me even more haha
To find the number of 4-digit combinations using numbers 0-9, you can apply the concept of permutations.
In this case, we need to find the number of permutations of 4 elements taken from a set of 10 (numbers 0-9) without repetition. The formula to calculate this is:
nPr = n! / (n - r)!
Here, n is the total number of elements and r is the number of elements we want to select.
So, for our case, n = 10 (numbers 0-9) and r = 4.
Substituting these values into the formula:
10P4 = 10! / (10 - 4)!
= 10! / 6!
= (10 * 9 * 8 * 7 * 6!) / 6!
= 10 * 9 * 8 * 7
= 5,040
Therefore, there are 5,040 different 4-digit combinations that can be formed using numbers 0-9.