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How do I set this up and how do I solve:

The sum of two numbers is 20 The difference between 3 times the larger number and twice the smaller number is 40. What is the larger number?

  • Math -

    let the larger be x
    let the smaller be 20-x

    Now just translate ...
    three times the larger ---> 3x
    twice the smaller ---> 2(20-x)

    that "difference" is 40
    3x - 2(20-x) = 40
    3x - 40 + 2x = 40
    5x = 80
    x = 16

    the larger is 16

    (the smaller is 4)

  • Math -

    Reiny, thank you so much. You broke it down so it was easy to understand.

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