for a sateliite to have a speed of 7400 m/s how far must it be in metres above the earth's surface
solve for h.
M V^2/R = M*g*(Re/R)^2
(due to inverse square falloff in weight with R)
Re is the earth's radius = 6370*10^3 m.
R = Re^2*g/V^2 = 7.262*10^6 m = 7262 km
Distance above Earth = 7262 - 6370 km = 892 km