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physics

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for a sateliite to have a speed of 7400 m/s how far must it be in metres above the earth's surface

  • physics -

    V^2/(re+h)=9.8(re/(re+h))^2
    solve for h.

  • physics -

    M V^2/R = M*g*(Re/R)^2
    (due to inverse square falloff in weight with R)

    Re is the earth's radius = 6370*10^3 m.
    R = Re^2*g/V^2 = 7.262*10^6 m = 7262 km

    Distance above Earth = 7262 - 6370 km = 892 km

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