Math Log
posted by beyonce knowles .
How do you find log20, if log2=.301?? Please show work

log20 = log(10*2) = log10 + log2 = 1+log2 = 1.301
Respond to this Question
Similar Questions

math
write as a single logarithm: 2logbase3(1/x)+(1/3)logbase3(square root of x) please show the steps to solving this. thanx. remember that 1 log (AxB) = log A + Log B (same base) 2 log (A/B) = log A  log B 3 log A^n = n log A use these … 
Math  Logarithmic
Solve: 2^(5x6) = 7 My work: log^(5x6) = log7 5x  6(log2) = log7 5x = log7 + 6(log2) x = (log7 + log2^6) / 5 And textbook answer: (log7) / (log2) What did I do wrong? 
Logarithms
I'm working on logarithmic equations and I'm stuck on how my book arrives at the next step. First, they use the change of base formula on, log(sqrt(2))(x^3  2) (sqrt(2)) is the base,changing to base 2 log(sqrt(2))(x^3  2)= log2(x^3 … 
precalculus
find the exact value of the following logarithm. Use the properties of logarithms show all work. log2 34log2 17 (Those are little two's) 
math30
1.Use the laws of logarithms to express log2 (6) â€“ log2 (3) + 2log2 (8)^1/2 as a single logarithm; then evaluate. 2. For logy = log(0.5x â€“ 3) + log2, express y as a function of x. 
Math
The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8. I use the change of base formula and got log6/log2 * log8/log6 Which become log6/log2 * log2()^3/ log 6 I'm stuck here thanks. 
algebra/please can you ck my answers
Tell what the output value is for the function machine for the given values. log 16.9=1.23 log2^152=9 log2^1=0 log0.046=1.34 thank you 
Math
1. The sequence log2 32, log2 y, log2 128, ... forms an arithmetic sequence. What is the value of y? 
Math
Hello! Could someone please take a look at the problem below and let me know if I made mistakes in simplifying the given equation? 
precalc
I don't understand how to do these w/o calc. I tried to write it in a way that will make someone understand how to read it. Hope I typed it clear enough.Thanks so much for the help anyone! How to find the exact value of logarithm: …