calculus

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I'm having trouble with these two problems. If someone can help me with the first one I can probably get the second one on my own. I think that I have to factor the bottom but I just cant get it.

lim (3x+7)/(8x^2-3x+11)
x-> infinity

  • calculus -

    multipy numerator and denomiantor by 1/x^2

    lim (3/x+7/x^2)/(8-3/x+11/x^2)

    lim numerator is zero
    lim denominator is 8

    lim then must be zero.

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