solving algebraic equation

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a movie theater charges $9 for an adults ticket and $5.00 for a child ticket. on a recent night the sale of child's tickets was two times the sale of an adults tickets. if the total amount collected for ticket sales was not more than $3800 what is the greatest number of adults who could have purchase tickets.

  • solving algebraic equation -

    If x = adult tickets, then 2x = children's tickets

    9x + 5(2x) < 3800

    Solve for x.

  • solving algebraic equation -

    200

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