Alg 2

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Solve the equation. Check for extraneous solutions.
ln x + ln(x-2) = 1

• Alg 2 -

lnx + ln(x-2) = 1 , where x>2
ln(x(x-2)) = 1
x^2 - 2x = e^1
x^2 - 2x + 1 = e+1 , ( I completed the square)
(x-1)^2 = e+1
x - 1 = ± √(e+1)
x = 1 ± √(e+1)
but x > 2 , so

x = 1 + √(e+1)

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