Aluminum reacts with hydrochloric acid to produce aluminum chloride and hydrogen gas. What mass of hydrochloric acid reacts when 87.7 grams of aluminum dissolves? The equation is 2Al+6HCl=2AlCl3+3H2
Here is a worked example of a stoichiometry problem. Just follow the steps.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To find the mass of hydrochloric acid that reacts when 87.7 grams of aluminum dissolves, we need to use the stoichiometry of the reaction.
The stoichiometry of the balanced chemical equation tells us that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 2 moles of aluminum chloride and 3 moles of hydrogen gas.
First, we need to convert the mass of aluminum to moles by using its molar mass. The molar mass of aluminum (Al) is 26.98 grams per mole.
Number of moles of aluminum = Mass of aluminum / Molar mass of aluminum
Number of moles of aluminum = 87.7 g / 26.98 g/mol = 3.249 moles
According to the stoichiometry of the reaction, 2 moles of aluminum react with 6 moles of hydrochloric acid. So, we can set up a ratio:
2 moles Al / 6 moles HCl = 3.249 moles Al / x
Cross-multiplying, we get:
2 moles Al * x = 6 moles HCl * 3.249 moles Al
x = (6 moles HCl * 3.249 moles Al) / 2 moles Al
x ≈ 9.747 moles HCl
Finally, we can convert the moles of hydrochloric acid to grams by multiplying by its molar mass. The molar mass of hydrochloric acid (HCl) is 36.46 grams per mole.
Mass of hydrochloric acid = Moles of hydrochloric acid * Molar mass of hydrochloric acid
Mass of hydrochloric acid = 9.747 moles * 36.46 g/mol
Mass of hydrochloric acid ≈ 354.7 grams
Therefore, approximately 354.7 grams of hydrochloric acid will react with 87.7 grams of aluminum.
To determine the mass of hydrochloric acid that reacts when 87.7 grams of aluminum dissolves, we need to use the stoichiometry of the balanced chemical equation.
The balanced equation is: 2Al + 6HCl = 2AlCl3 + 3H2
From the equation, you can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 2 moles of aluminum chloride and 3 moles of hydrogen gas.
1. First, calculate the number of moles of aluminum based on its mass. To do this, divide the mass of aluminum by its molar mass. The molar mass of aluminum is 26.98 g/mol.
Number of moles of aluminum = mass of aluminum / molar mass of aluminum
= 87.7 g / 26.98 g/mol
2. Now, using the stoichiometric ratio from the balanced equation, determine the number of moles of hydrochloric acid that react with the calculated moles of aluminum.
According to the balanced equation, 2 moles of aluminum react with 6 moles of hydrochloric acid.
So, the number of moles of hydrochloric acid = (number of moles of aluminum) × (moles of HCl / moles of Al)
= (87.7 g / 26.98 g/mol) × (6 mol HCl / 2 mol Al)
3. Finally, convert the moles of hydrochloric acid to grams by multiplying with the molar mass of hydrochloric acid. The molar mass of HCl is 36.46 g/mol.
Mass of hydrochloric acid = (number of moles of hydrochloric acid) × (molar mass of HCl)
= [(87.7 g / 26.98 g/mol) × (6 mol HCl / 2 mol Al)] × (36.46 g/mol)
Performing these calculations will give you the mass of hydrochloric acid that reacts with 87.7 grams of aluminum.