Physics

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A force of 1000 N is applied to a 1200 kg car. If the coefficient of friction is 0.04, what is the car's acceleration?

  • Physics -

    a = Fnet/m

    The net force is
    Fnet = 1000 - M*g*Uk
    = 1000 - 470.4 = 529.6 N

    a = 529.6/1200 = 0.441 m/s^2

  • Physics -

    thank you!

  • Physics -

    how did you cope in this answer what is the formula and solution?

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