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give exact and approximate to three decimals places x^2+8x+16=25 Please help me solve this

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    x^2+8x+16-25 = 0,
    x^2+8x-9 = 0,
    (x+9(x-1) = 0,

    x+9 = 0,
    X = -9.

    x-1 = 0,
    X = 1.

    Solution set: X = -9, and X = 1.

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