posted by .

3+siny = 3cos^2 y for 0<Y<360

  • math -

    I bet if you used
    cos^2 Y= 1-Sin^2 Y

    you would end up with a quadratic equation. If you are stuck, let x=SinY, and solve it that way.

  • math -


Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Maths

    Solve this equation fo rx in the interval 0<=x<=360 3sinxtanx=8 I would do it this way: sinxtanx = 8/3 sinx(sinx/cosx)=8/3 sin^2x/cosx = 8/3 (1-cos^2x)/cosx=8/3 cross-multiply 3 - 3cos^2x = 8cosx 3cos^2x + 8cosx - 3 = 0 (3cosx-1)(cosx+3)=0 …
  2. Math

    Find y'(x) when cos y - y^2 = 8 a) -siny - 2y b) - (1/sin y - 2y) c) 0 d) - (8/cos y - y) So if I implicitly differentiate: y'(x) = -sin(y) - 2y y' = 0 Am I right to say that there's nothing more you can do to this and pick C?
  3. trig

    Okay, I've been getting some of these, but I can't seem to verify this identity... any help?
  4. pre cal

    Verify each identity sin^x+siny/sinx-siny=tan(x+y/2) (times) cot(x-y/2)
  5. maths

    find the range of sin(siny)+cos(siny)
  6. maths---urgently needed

    range of sin(siny) +cos(siny)
  7. maths

    solve 3cos^2 2x +4 sin 2x =1 0<x<360
  8. math

    determine the amplitude and period for each function: y=4sin x, y=2sin4x,y=-3sin2pi x, y=-3cos x, y=-3cos pi over 2 x
  9. Calculus Question! ASAP!

    Hello! I have this problem: x(dx)/sqrt(9-x^2) I was wondering why I can't use trig substitution and substitute sqrt(9-x^2) for sqrt(1-sec^2) and having: integral x = 3sin(theta) dx = 3cos(theta)d(theata) integral 3sin(theta)(3cos(theta))/3cos(theta) …
  10. Math - Linear Approximation

    I have a follow-up question from a problem I posted earlier: Approximate sin(61π/360): So, sin(60π/360 + π/360) = sin(π/6 + (π/360)) Now the equation for linear approximation is f(x+a)=f(a)+f'(a)(x-a). To get the right answer, …

More Similar Questions