the perimeter of a rectangle is 12 c.m and its length is 4 c.m . what is its width? and the area?
P = 2L + 2W
A = LW
width - 2 cm: length + length = 8 cm there are 4 cm left, 4 divided by 2 = 2
area - 8 like ms.sue said
area = length x width,
perimeter= 2length x 2width
To find the width of a rectangle, we can use the formula for perimeter. The formula for the perimeter of a rectangle is given by P = 2(L + W), where P stands for perimeter, L represents the length, and W represents the width.
In the given problem, we are told that the perimeter of the rectangle is 12 cm and the length is 4 cm. Let's substitute these values into the formula and solve for the width:
12 = 2(4 + W) // Substitute P = 12 and L = 4 into the formula
12 = 8 + 2W // Simplify the expression within the parentheses
12 - 8 = 2W // Move 8 to the other side of the equation by subtracting it from both sides
4 = 2W // Simplify
2 = W // Divide both sides by 2 to solve for W
So, the width of the rectangle is 2 cm.
To find the area of a rectangle, we can use the formula A = L × W, where A stands for area, L represents the length, and W represents the width.
Using the given length of 4 cm and width of 2 cm, we can substitute these values into the formula:
A = 4 × 2 // Substitute L = 4 and W = 2 into the formula
A = 8
So, the area of the rectangle is 8 square cm.