mathcalculus
posted by Shreya .
2x32x+5 = 0 i please need helps with this.

if 2x3 >= 0 then you have
2x3  2x5 = 0
Now, if 2x5 >= 0, that gives
2x3  (2x5) = 0
2 = 0
no good
If 2x5 < 0 you have
2x3  (2x5) = 0
2x3 + 2x5 = 0
4x  8 = 0
x = 2
since x=2 satisfies both conditions
2x56 < 0 and 2x3 >= 0, it's a solution.
Work through the other possibilities to find that x=2 is the only solution.
Makes sense, since the graphs of the two absolute values are vshaped with equal slopes, so they intersect in only one point.
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