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differentiate y=tanx^2/1+cosx and y=e^x^3-tan6x

  • math -

    I will assume you meant
    y = tan (x^2) / (1 + cosx)
    by quotient rule,
    dy/dx = ( (1+cosx)(sec^2 (x^2))(2x) - tan x^2 (-sinx) )/(1+cosx)^2
    I don't know what level of simplification you need

    y = e^(x^3) - tan 6x
    dy/dx = (3x^2)e^(x^3) - 6 sec^2 (6x)

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