math/calculus
posted by Angie .
find f"(x) if f(x)= cube root(x^22x+1)

Note that x^2  2x + 1 = (x1)^2
f(x) = (x1)^2/3
f' = 2/3 (x1)^1/3
f'' = 2/9 (x1)^4/3
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