physics
posted by ted .
The specific heat of pure water at 15 degrees celsius is 4184j/(kg.k). Convert this to kcal/(kg.k).
pls help

4184j/kgK ( 1K/1C)(XXX Kcal/j)
so, what is the conversion factor for Kcal to J?
1 KCal= 4184joules
4184j/kgK ( 1K/1C)(1Kcal/4184j)= ?
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