physics
posted by maria .
Suppose 0.0210 kg of steam (at 100.00°C) is added to 0.210 kg of water (initially at 19.5°C.). The water is inside a copper cup of mass 48.9 g. The cup is inside a perfectly insulated calorimetry container that prevents heat flow with the outside environment. Find the final temperature (in °C) of the water after equilibrium is reached.
use the following values:
c_copper=0.386 kJ/kg.K
c_water=4.19 kJ/kg.K
L_fusion=2.26 MJ/kg

The sum of heats gained=0
Heatwater+heatsteam+heatcopper=0
.210*cw*(tf19.5)kJ+.0210*2.26Mj/kg+.0210*cw*(tf100)+.0489*cc*(tf19.5)=0
solve for tf