# trig

posted by .

find all solutions of 2sinx=1-cosx in the interval from 0 to 360

• trig -

square both sides.

4sin^2= 1-2cos+cos^2
4(1-cos^2)=1-2cos+cos^2

now, gather terms, it is a quadratic, solve using the quadratic equation.

• trig -

okay so i got -(3/5) and 1, i am supposed to find the solutions in the interval from 0degrees to 360degrees

• trig -

the previous ans. is wrong as if we sq. the eqn. it generates false solutions a better method is to divide coefficients of sin and cos by root of sq. of coeff.ofsin+sq. of coeff of cos . that is main pt. remaining we will proceed by making it an argument in cos . and then make general sol. and find no. of sol. or diff solutions by putting value of n in general solution

• trig -

the previous ans. is wrong as if we sq. the eqn. it generates false solutions a better method is to divide coefficients of sin and cos by root of( sq. of coeff.ofsin+sq. of coeff of cos) . that is main pt. remaining we will proceed by making it an argument in cos . and then make general sol. and find no. of sol. or diff solutions by putting value of n in general solution

## Similar Questions

1. ### maths

hey, i would really appreciate some help solving for x when: sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x 2sinxcosx - cosx = 0 cosx(2sinx - 1)=0 cosx = 0 or 2sinx=1, yielding sinx=1/2 from cosx=0 and by looking …
2. ### trig

Find all solutions of the equation 2sin^2x-cosx=1 in the interval [0,2pi) x1= ?
3. ### Math - Trig

I need to find the solutions in the interval [0, 2pi for: 2sinx + cosx = 0 Im trying to get it where I can split two things up and set them equal to zero but that can only be done when they are being multiplied to each other, but as …
4. ### Trigonometry

Solve for x in the interval 0<=x<360: 1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
5. ### trig

Solve for [0, 360) 2sinxcosx + cosx =0 2sinxcosx = -cosx 2sinx = -cosx/cosx sinx = -1/2 {210, 330) Is this correct?
6. ### mathematics

Find all the solutions of 2 sinx=1-cosx in the interval from 0° ≤x<360°
7. ### trig

Find all the solutions of 2 sinx=1-cosx in the interval from 0° ≤x<360°
8. ### Trig (Last URGENT)

sin2x+cosx=0 , [-180,180) = 2sinxcosx+cosx=0 = cosx(2sinx+1)=0 cosx=0 x1=cos^-1(0) x1=90 x2=360-90 x2=270 270 doesn't fit in [-180,180) what do I do?
9. ### trig

Find all solutions in the interval [0,360) sin(4t)=ã3/2
10. ### Trig

find all solutions of 2sinx=1-2cosx in the interval from 0 to 360

More Similar Questions