physics

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A 1680- kg rocket is launched with a velocity v0 = 55 m/s against a strong wind. The wind exerts a constant horizontal force Fwind = 15600 N on the rocket. At what launch angle will the rocket achieve its maximum range?

  • physics -

    horizontalacceleration= F/m

    distance horzontal due to force= 1/2 F/m*t^2

    distance horizontal= 55*cosTheta*t+1/2 F/Mass*t^2

    Now, time in air:
    hf=hi=0=55sinTheta*t-1/2 g t^2

    or t= 110sinTheta/g
    put that time in distance horizontal, then take the derivative of distance/dt and set to zero, solve for theta.

    Interesting question.

  • physics -

    I DON'T UNDERSTAND.
    WHAT IS: distance horzontal due to force= 1/2 F/m*t^2

    and what do you mean by:
    put that time in distance horizontal, then take the derivative of distance/dt and set to zero

    if you can explain in more details it will help

    thanks alot

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