# Pre-Calculus

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Need help with the following along with all steps.

Find y" for y = 3x + 4/x

• Pre-Calculus -

write it as

y = 3x + 4x^-1

y' = 3 - 4x^-2
y'' = 8x^-3 or 8/x^3

• Pre-Calculus -

Thank you so much for your help. Now that I look at it more closely. I understand what I wasn't seeing!

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