# Math

posted by .

A = h/2 (a+b)

the subject of the given formula is "a" not "A"

please include workings (along with solution) thanks

• Math -

this topic that i learned in class is "changing the subject of a formula" FYI

• Math -

Use algebra to derive the formula for a in terms of h, A and b.

You should use parentheses to show if (a+b) is part of the denominator of a fraction h/[2(a+b)], or not. I will assume you mean
A = (h/2)*(a+b)

a + b = 2A/h

a = 2A/h -b

• Math -

God bless you. Thanks!

## Similar Questions

1. ### To Desire

Your posts have been removed, mainly because you have given absolutely no thought to how you'll solve those problems in your assignment. In the future, please remember these things: 1. This is a homework help website; please put your …
2. ### Math

5 4 ______ - ______ 2(e-f) 3(f-e) Please include workings thx
3. ### Math

4C/(10C-5D) + 2D/(6C-3D) Please include workings thx
4. ### Math - 2 Questions

1. (1/4)C/C+(1/3) 2. (1/X)+(1/Y)/(2/X) Please include workings and thank you in advance
5. ### Math

S = n/2 (a+1) The subject of the formula is L Same as before, please include workings TYVM
6. ### Math

Sorry for repeated questions, but this is my last problem: s = ut + 1/2(gt) The "t" for "gt" is squared, and the subject of the formula is "u". Thank you very much (and please include workings).