calculus
posted by Emily .
The hypotenuse of a right triangle has one end at the origin and one end on the curve y = (x^4)(e^7x), with x > 0. One of the other two sides is on the xaxis, the other side is parallel to the yaxis. Find the maximum area of such a triangle.

area=1/2 y x
but y=above, so
area=1/2 x^5(e^7x)
darea/dx=5/2 x^4(e^7x)7/2 x^5(e^7x)=0
divide by x^4 e^7x
0=5/2 7/2x
x=5/7
y=you do it, then solve for Area.
check my work.