calculus
posted by John .
y sin 12x = x cos 2y, (pi/2, pi/4)
Find the tangent line to the curve at the given point.
y=???

dy/dx * sin12x+ 12 y cos12x= cos2yxsin2y dy/dx
dy/dx(sin12x+xsin2y)=cos2y12ycos12x
first, solve for dy/dx, that is the slope.at x,y.
y= mx+b
Now put in the x,y in that equation, and solve for b. 
Can anyone else elaborate?
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