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.850L of .410M of H2SO4 is mixed with .800L of .200M of KOH. what is the concentration of sulfuric acid

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    2KOH + H2SO4 ==> K2SO4 + 2H2O
    moles H2SO4 = M x L = ?
    moles KOH = M x L = ?
    It takes 1/2 mole H2SO4 for every mole of KOH so we use 0.080 moles H2SO4.
    How much H2SO4 remains? That will be moles H2SO4 - 1/2 moles KOH = ??
    Then M H2SO4 = moles remaining/total volume in liters.

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