posted by cox .
.850L of .410M of H2SO4 is mixed with .800L of .200M of KOH. what is the concentration of sulfuric acid
2KOH + H2SO4 ==> K2SO4 + 2H2O
moles H2SO4 = M x L = ?
moles KOH = M x L = ?
It takes 1/2 mole H2SO4 for every mole of KOH so we use 0.080 moles H2SO4.
How much H2SO4 remains? That will be moles H2SO4 - 1/2 moles KOH = ??
Then M H2SO4 = moles remaining/total volume in liters.